I got this practice exam question the other day but dont understand it...
If the voltage between the neutral and the peak of a three-phase current is 120 volts, what is the voltage between two phases?
the answer is below. but first off what is a "neutral" and what is "the peak"? Where did this equation come from?
V2 = V1 / square root of 3
V1 = V2 x square root of 3 = 120vx1.73 = 208v
Any help would be greatly appreciated. Also, some images are attached from the book. how do you know for instance the 3 phase transformer schematics image that between the lines it 240v or 120v between two other lines?
Hope this makes sense..
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