Frontage Increases
Say you are calculating the frontage increase and the dimension of open space is over the 20' minimum but below the 30.' Say, the number is 24', would you use 24' as the W or would you just use 20' since it is over the minimum? I'm looking at this problem here:
and I'm wondering why they used 20' and not 24' as the W.
Thanks.

Hi Mark,
I wondered the same thing about that particular question. It looks like it was a Ballast typo and they fixed it in the second printing. Their errata page says this:
"The value in the 2nd printing as this erratum refers to is 20 feet. It was incorrectly given as 24 feet in the first printing and was corrected for the 2nd printing."
Translated: the question should read that the open space is 20 ft wide. So, you're right  that question as written should use 24 as the W.
Stephanie

I encountered a similar problem while studying Chings Building Codes Illustrated. the value of W is used 40 in the first example while 50 on the other, but i don't understand why they did not use the weighted average formula instead? W = (L1 X w1 + L2 x w2 + L3 x w3 + ...)/F. can anyone help?

i've always found Asra's questions and answers to be spot on. so i took note of this when i first reviewed the thread.
not sure if her question will be tested but i also find this issue in Building Construction Illustrated to be confusing. tried to track it down through 2012 and 2010 version and it seems to me that there may be some typos here?
anyway, started a thread to try and resolve it since at the very least it would be nice to know even if it is not a test item in ARE.
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